Rapport éventuel avec la sur-unité d'une bobine alimentée par des "pics" de H. T (kicks)
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| P = 0.05 x f x A x L , (where P is in watts).
A is the section of the coil in m2, f the frequency in Hertz, L the coil former length in metres To cancel the Earth's magnetic field inside the coil, the condition based on Ampere's law is: N x i / L = 100 Where N is the number of turns on the coil and i is the current in amperes. Finally, the induced voltage in the coil will be: V = 2 x pi x f x N x Bo x A So, with the following values, we have for example: N = 1000 turns, f = 100 kHz, Coil diameter = 1 m, Coil length L = 1 m, i = 100 mA or 0.1 A, Bo = Earth's magnetic field This gives V = approximately 4,000 Volts. The input power for this example is about 4 kW, the output power for the COP factor will be a maximum of 12 kW. In closed-loop operation we provide the input 4 kW from the generated output and we get a self-powered generator producing 8 kW of output power. My practical results match these calculations. How is a practical device built? Using a large plastic pipe, we wind the primary input coil for use with the external source. For extracting the output power, we use another pipe placed inside the first pipe, and of approximately the same diameter and length with an adequate number of turns and wire size to step down the voltage, to, for example, 110 VAC. For the high voltage oscillator of the input source I use a resonant LC circuit taken from a ferrite power transformer. It is very interesting to see this device work, and on days of geomagnetic storms, power levels go too high and I must use protective devices to prevent damage to the system and the loads connected to it. Any questions to the following email: enertec2200@yahoo.es (which may not still be operational as this information is quite old). Download 10.18 Kb. Share with your friends:
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