Example 2.2.08 (continued)
Reducing the augmented matrix to row-echelon form:
which is equivalent to
 and
The leading variables are x 1 and x 3 .
Assign parameters x 2 = r, x 4 = s, x 5 = t, so that the general solution is
Then
The basic solutions are therefore
X1 = [ –2 1 0 0 0 ]T , X2 = [ –1 0 1 1 0 ]T , X3 = [ –1 0 4 0 1 ]T
and the general solution to AX = O is X = r X1 + s X2 + t X3 .
Therefore the complete solution to AX = B is
X = [ 1 2 0 2 1 ]T + r X1 + s X2 + t X3 .
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