Experiment title

13
Experiment 2:

𝑄𝑡 =
6.6𝑥10^ − 4𝑥2.27𝑥10^ − 4√2𝑥9.81𝑥0.193
√(6.6𝑥10
−4
)²𝑥(2.27𝑥10
−4
)²
Qt=4.7023x10^-4 ms. Experiment No. Difference in Height of Manometer, H (m. Theoretical Discharge,
Qt x (ms)
1 0.245 1.823 2
0.193 2.580 3
0.133 3.230 4
0.091 3.900 5
0.058 4.702 6
0.029 5.300
Table 1.7: Results of Theoretical Discharge.
Calculation Of actual discharge, Qa:
Qa Volume of liquid in the tank
Time in sec
Constant volume in the tank = L =0012 mi bExperiment 1:
𝑄𝑎 =
0.012𝑚³
23.22𝑠
Qa=5.17x10^-4 ms.
Experiment 2:
𝑄𝑎 =
0.012𝑚³
26.60𝑠
Qa = x ms.

14 Experiment No. Volume in Tank, V (m. Time (Sec. Actual Discharge,
Qax10^-4 (ms.
1 0.012 23.22 5.17 2
0.012 26.60 4.5113 3
0.012 32.72 3.67 4
0.012 39.19 3.06 5
0.012 51.45 2.3324 6
0.012 76.34 1.572
Table 1.8: Results of Actual Discharge.

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