In a network with two or more sources, the current or voltage for any component is the algebraic sum of the effects produced by each source acting separately
Principle of duality in context of electrical networks states that. A dual of a relationship is one in which current and voltage are interchangeable. Two networks are dual to each other if one has mesh equation numerically identical to others node equation
instantaneous power refers to the power consumed at a particular point in time
A phenomenon in which an external force or a vibrating system forces another system around it to vibrate with greater amplitude at a specified frequency of operation.
The quality factor Q for the circuit is the electric energy stored in the circuit divided by the energy dissipated in one period.
Part B & C
11 a)i) Convert Voltage Source into current source
Apply KVL and find the loop current
Repeat the Process for the second source
Add Both the currents to get current through 5 Ohms
Current through 5 ohm is :0.2A
ii) Mesh Equations
Solving we get i1=1.5A, i2=0.5A,i3=0.9A
11 bi) Apply Nodal Analysis method
Power Delivered: 3.3w
I = 3 (2/( 2 + 2)) = 1.5 A,V=1.5 *2=3V
12a) For the circuit shown below, find the current L I through 6 Ω resistor using Thevenin’s theorem.
Thevenin’s Equivalent Circuit
12 b) For the circuit shown below, find the value of RL that absorbs maximum power from the circuit and the corresponding power under this condition.
Vab =10 v
To computute RTh
the maximum power dissipated to RL= 0.625 watts.
13 a i)
13 aii) RN= 7.5ohm+johms
IN= 26.5angle (-10.3)
General Circuit Diagram
Equations Over Damped, Under Damped and Critically Damped
i(0) _ 4 A
s1 _ _11.978, s2 _ _0.5218
A2 _ 0.0655
A1 _ _0.0655
15. a) Statement :
Dot Convention in Coupled Circuits is used to establish the choice of correct sign for the mutually induced voltages in coupled circuits. Circular dot marks and/or special symbols are placed at one end of each of two coils which are mutually coupled to simplify the diagrammatic representation of the windings around its core.
Analysis with equation
15.b i)Circuit Diagram
Explanation with theory
15bii) Answers :−1.5, 2.5, 3.5 H; 5.5, 9.5, −3.5 H.
16a) Tie Set Matrix-2 Marks
Determinant Matrix -2 Marks
possible number of trees = 12
The corresponding graph, tree, co-tree, and loops 1, 2, 3:4 Marks
Loop Current Matrix-2 Marks
Possible Tree and Co-Tree (3 Marks)
Tie-set schedule:((6 Marks)
Tie Set Matrix
The branch impedance matrix
The loop impedance matrix
The loop equations :(6 Marks)
x = 4.1666 A, y = 1.16666 A, z = 2.5 A
The branch currents
I1 = x = 4.1666 A, I2 = y = 1.6666 A, I3 = z = 2.5 A, I4 = x − z = 1.6666 A, I5 = −x + y = −2.5 A, I6 = −y + z = 0.8334 A
The branch voltages
V1 = 5I1 − 50 = 29.167 V, V2 = 10I2 = 16.666 V, V3 = 5I3 = 12.50 V, V4 = 10I4 = 16.666 V, V5 = 5I5 = −12.50 V, V6 = 5I6 = 4.167 V
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