Enrichment Activities:
Along a 100 m. length in a fairly level ground, an Engineering Student walks five times and gathered the number of paces as follows: 137, 135, 136, 135, 137.
Just after the activity, the student counted his paces at two points A and B on the ground and recorded an average of 76.50 paces. Find :
Pace factor
Paced distance of line AB.
Solutions:
Mn= 137+135+136+135+137 /5
Mn=136 paces (p)
PF= L / Mn
PF= 100 m / 136 p
PF=0.73 m/p Answer.
Paced Distance (PD) = PF x Mn
Mn= 76.50 p
PD= 0.73 m/p x 76.50 p (cancel p)
PD = 55.84 m Answer
A Surveyor counted his number of steps in an unknown distance. An average of 165.5 paces were recorded. If his pace factor is 0.73 m/p., find the unknown distance.
Solution: Given: Mn= 165.5 paces
PF= 0.73 m/p
PD= Unknown
PD= PF x Mn
PD= 0.73m/p x 165.5 p (cancel p)
PD= 120.82 m. Answer
Share with your friends: |
