12.7 Mathematical Cleanup
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Are there important details that haven’t been addressed in the presentation of utility maximization?
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What happens when consumers buy none of a good?
Let us revisit the maximization problem considered in this chapter to provide conditions under which local maximization is global. The consumer can spend M on either or both of two goods. This yields a payoff of h(x)=u(x,M−pXxpY). When is this problem well behaved? First, if h is a concave function of x, which implies h″(x)≤0, [1]then any solution to the first-order condition is, in fact, a maximum. To see this, note that h″(x)≤0 entails h′(x) is decreasing. Moreover, if the point x* satisfies h′(x*)=0, then for x ≤ x*, h′(x)≥0; and for x ≥ x*, h′(x)≤0, because h′(x) gets smaller as x gets larger, and h′(x*)=0. Now consider x ≤ x*. Since h′(x)≥0, h is increasing as x gets larger. Similarly, for x ≥ x*, h′(x)≤0, which means that h gets smaller as x gets larger. Thus, h is concave and h′(x*)=0 means that h is maximized at x*.
Thus, a sufficient condition for the first-order condition to characterize the maximum of utility is that h″(x)≤0 for all x, pX, pY, and M. Letting z=pXpY, this is equivalent tou11−2zu12+z2u22≤0 for all z > 0.
In turn, we can see that this requires (i) u11 ≤ 0 (z = 0), (ii) u22 ≤ 0 (z→∞), and (iii) u11u22‾‾‾‾‾‾√−u12≥0 (z=u11u22/‾‾‾‾‾‾‾√). In addition, since
−(u11+2zu12+z2u22)=(−u11‾‾‾‾‾√−z−u22‾‾‾‾‾√)2+2z(u11u22‾‾‾‾‾‾√−u12),
(i), (ii), and (iii) are sufficient for u11+2zu12+z2u22≤0.
Therefore, if (i) u11 ≤ 0, (ii) u22 ≤ 0, and (iii) u11u22‾‾‾‾‾‾√−u12≥0, a solution to the first-order conditions characterizes utility maximization for the consumer.
When will a consumer specialize and consume zero of a good? A necessary condition for the choice of x to be zero is that the consumer doesn’t benefit from consuming a very small x; that is, h′(0)≤0. This means that
h′(0)=u1(0,MpY/)−u2(0,MpY/)pXpY/≤0
or
u1(0,MpY/)u2(0,MpY/)≤pXpY/.
Moreover, if the concavity of h is met, as assumed above, then this condition is sufficient to guarantee that the solution is zero. To see this, note that concavity of himplies h′ is decreasing. Combined with h′(0)≤0, this entails that h is maximized at 0. An important class of examples of this behavior is quasilinear utility. Quasilinear utility comes in the form u(x, y) = y + v(x), where v is a concave function (v″(x)≤0 for all x). That is, quasilinear utility is utility that is additively separable.
Figure 12.14Quasilinear isoquants
The procedure for dealing with corners is generally this. First, check concavity of the h function. If h is concave, we have a procedure to solve the problem; when h is not concave, an alternative strategy must be devised. There are known strategies for some cases that are beyond the scope of this text. Given h concave, the next step is to check the endpoints and verify that h′(0)>0 (for otherwise x = 0 maximizes the consumer’s utility) and h′(MpX/)<0(for otherwise y = 0 maximizes the consumer’s utility). Finally, at this point we seek the interior solution h′(x)=0.With this procedure, we can ensure that we find the actual maximum for the consumer rather than a solution to the first-order conditions that don’t maximize the consumer’s utility.
KEY TAKEAWAYS -
Conditions are available that ensure that the first-order conditions produce a utility maximum.
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With convex preferences, zero consumption of one good arises when utility is decreasing in the consumption of one good, spending the rest of income on the other good.
EXERCISE -
Demonstrate that the quasilinear consumer will consume zero X if and only if v′(0)≤pxpy, and that the consumer instead consumes zero Y if v′(MpX/)≥pxpy. The quasilinear utility isoquants, for v(x)=(x+0.03)0.3, are illustrated in Figure 12.14 "Quasilinear isoquants". Note that, even though the isoquants curve, they are nonetheless parallel to each other.
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