Drag Force and Terminal Velocity Problems Fishbane Chp 5


The maximum acceleration is achieved when there is no drag (low speed)



Download 459.96 Kb.
Page4/6
Date20.05.2018
Size459.96 Kb.
#49461
1   2   3   4   5   6

The maximum acceleration is achieved when there is no drag (low speed).

Thus Fengine = ma = (800 kg)(4.8 m/s2) = 3.8103 N.

At a top speed of vmax = 90 m/s, the acceleration is zero and

so

CD = 2Fengine/Av2 = 2 (3.8103 N)/(1.25 kg/m3)(1.8 m2)(90 m/s)2 = 0.42.
P44. Assume that the drag force on a parachute is given by Eq. (5–30) in the text. The

effective area of the parachute is and the density of air is If a 90-

kg parachutist finds that his terminal speed is what is the drag coefficient?



Download 459.96 Kb.

Share with your friends:
1   2   3   4   5   6




The database is protected by copyright ©ininet.org 2024
send message

    Main page