= 2(90 kg)(9.8 m/s2)/(1.25 kg/m3)(30 m2)(6 m/s)2 = 1.3.
P45. A parachutist of 60-kg mass uses a parachute similar to the one used by the
parachutist of the previous problem. Determine the terminal speed of this lighter
person.
Similar to the previous problem, set  which gives v = constant m1/2. With m1 = 90 kg, v1 = 6 m/s, and m2 = 60 kg, the terminal speed v2 of the 60-kg person must satisfy
v1/ v2 = (m1/ m2)1/2 , which gives
v2 = (m2/ m1)1/2 v1 = (60 kg/90 kg)1/2 (6 m/s) = 5 m/s.
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