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Part with an electric field and no magnetic field: electron  negative charge



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Part with an electric field and no magnetic field: electron  negative charge

e.)






8.) In the long solenoid [shown in cross section] in the figure to the right, the magnetic field varies according to the equation:

B(t) = (2.00 t3 – 4.00 t2 + 0.800) T.

The radius of the solenoid is R = 2.5 cm and r2 = 5 cm. Calculate the magnitude and direction of the force on an electron at P2 at time t = 2 s. When would the force on that electron be zero?









The circle is an E line chosen to circulate in the CCW sense.

The path should be concentric with the solenoid. I missed just a little!



The electric field circulates around . If is into the page, E circulates in the out of the page sense (CCW).






E circulates CCW for Bt > 0.

If r < R, then fills all the area enclosed by the E field line path.



(r < R)

If r > R, then fills the area out to R only



(r > R)

Solving for E and adding our CCW sense convention:



For r < R, the path is completely filled with time varying B field. For r > R, the path is only filled with time varying B field for the central circle of radius R. The magnetic field is non-zero only inside the solenoid.


B(t) = (2.00 t3 – 4.00 t2 + 0.800) TB/t = (6.00 t2 – 8.00 t) T /s = 8.00 T /s for t = 2 s.

r2 > R so

The force on an electron will be or 8.01 x 10-21 N


The electric field is tangent to the concentric circular field lines in the CCW sense.

The force on an electron will be or 8.01 x 10-21 N tangent in the CW sense.


B/t = (6.00 t2 – 8.00 t) T /s vanishes for t = 0 s and t = 4/3 s. E will vanish at these times.

No Equation Sheet for the actual test !!!!!! Included for REVIEW only.
Constants
Electric Fields
Gauss’s Law
Electric Potential


Capacitance
Current and Circuits
Magnetic Fields

; ; ; ;



Induction/Inductance




Physics Handout Series – fields.tank with jeff and jeff page


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