Zero Point Energy doc
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| ZP OWER C ORPORATION PAGE OF 352 Z ERO P OINT E NERGY B ALANCING F REE E NERGY DEVICES B Y T HOMAS E. B EARDEN I think the way to "balance" the use of free energy may very well comedown to this First, you can reuse energy over and over. The only real conservation of energy law is that "energy can neither be created nor destroyed. Period" This means that, when you "use" a joule of energy (e.g., suppose you scatter a joule of incoming energy, in a resistor, then you still have that joule of energy remaining AFTER you've done a joule of work. So in May this year at the 4th International Energy Conference, I pointed out that you can RETROREFLECT the energy, after it's already "passed through" the circuit, and get it back (or some of it, depending on the reflection coefficient) to "reuse" (i.e. scatter) once again. I pointed out that this already occurs in intensely scattering media, and provides the well-known anti-Stokes emission phenomenon, which IS DEFINED as emission by the medium of more energy than one puts in In other words, the fact that one can get overunity has been recognized in the anti- Stokes emission phenomenon for over 30 years. Now all energy comes from the vacuum. Sorry about that to the electrodynamicists, but if they will read a little particle physics, it has been known for 40 years that any electrical charge or electrical dipole is a "broken symmetry" in the violent energy flux of the vacuum. That's a proven thing. By definition of "broken symmetry" in a virtual particle flux (which is what the vacuum energy is, particle physics tells us that ? (1) that asymmetrical portion (i.e., the "gated" portion or "extracted" portion) changes from virtual to "observable, and ? (2) that observable energy flow component will be radiating away from the charge or dipole. Note that electrodynamics doesn't even know what the whack an electrical charge is, much less a dipole There is presently no definition of electrical charge in physics. Anyway, the point is that any dipole ? (1) already freely extracts energy from the seething vacuum, due to the dipole's asymmetry in that flux, and ? (2) already puts out an observable flow of energy as a result. |