1st approach
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1st approach: Consider link AC, CE, EB, CF, FB, AD, DB as component 1, 2, 3, 4, 5, 6 and 7 then we can represent the network as 3 2
7 6 5 4 1 Then we can look at the network as a complicated system with parallel and series subsystem 2nd approach Consider 3 events A1, A2, A3 which are all the links in the paths ACEB, ACFB and ADB are up respectively And A is the event that there is a path connecting A and B in which all the links are up then Applying the addition formula, we have P( Download 36.16 Kb. Share with your friends:
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