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1st approach
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Date | 27.03.2023 | Size | 36.16 Kb. | | #60976 |
| Guide Exercise 2 Section 5 Chapter 1 (1)
1st approach: Consider link AC, CE, EB, CF, FB, AD, DB as component 1, 2, 3, 4, 5, 6 and 7 then we can represent the network as
3
2
7
6
5
4
1
Then we can look at the network as a complicated system with parallel and series subsystem
2nd approach
Consider 3 events A1, A2, A3 which are all the links in the paths ACEB, ACFB and ADB are up respectively
And A is the event that there is a path connecting A and B in which all the links are up then
Applying the addition formula, we have
P(
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