Rapport éventuel avec la sur-unité d'une bobine alimentée par des "pics" de H.T (kicks)
Many people think that it is not possible get power from the Earth magnetic field because that field intensity is too low and so the energy levels aren't high enough for any form of useful application. this is not the case. I have built many coils and I get many kilowatts for useful purposes from Earth's magnetic field and here I present the basic concept and some formulas fundamental to all of this.
The influence of the Earth's magnetic field should not be ignored. In times of strong sun activity, the Earth's magnetic field oscillates and in any long power transmission line there are voltage surges and over-voltages which can cause technical troubles, breakdowns and stoppages of the electrical sources. The Faraday law for that induction is given for the following:
V = 2 x pi x f x B x A
Where:
B is the Earth's magnetic field,
f the frequency of the fluctuations, and
A the surface area across which the field flows.
For calculation purposes we can approximate the Earth's magnetic field as being 1 Gauss (or 10-4 Teslas)
If we consider an ordinary, long transmission line of about 10 Km in length with the power lines spaced 1 metre apart, then we have:
V = 6.28 x 10-4 x 104 x f which equals 6.28 x f
If the fluctuations are f = 10 Hz, that produces an over-voltage of 63 V. If the fluctuations are 100 Hz then the over-voltage is 630 V, etc.....
So if the Earth's magnetic field is lower in intensity, the effect is considerable in a great surface and volume range.
For energy and power considerations, we can see that the Earth's magnetic field is lower than common permanent magnets, but the volume of space which it covers is very large. The energy in a magnetic field is not just the field intensity alone, but it depends also on the volume across which that field acts.
The energy stored in a magnetic field B across a space volume V is:
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