Subnetting a Class c address Example
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Subnetting a Class C Address Example You have been tasked with producing an addressing scheme to support five networks (subnets) within your LAN. You will be using the private class C address 192.168.10.0 /24. Step 1 – Determine how many network bits you will need to borrow from the available host bits. Use the formula 2n where n >= the number of networks needed. 2n >= 5 n=3 We will actually have 8 networks even though we only need 5 because 23 = 8 Step 2 – Change the subnet mask to reflect the value for n in step 1. Since n=3 add replace the first 3 zeros in the last octet to ones. The original subnet mask was 11111111.11111111.11111111.00000000 or 255.255.255.0 The new subnet mask is: 11111111.11111111.11111111.11100000 or 255.255.255.224 Step 3 – Determine how many hosts you will have available on each network Use the formula 2n -2 where n = the number of 0’s in your subnet mask 25-2 = 30 Step 4 – Determine the new network addresses Determine the decimal value of the last bit (the last 1) in the subnet mask. In our example the last 1 is in the 32 position so our networks will be in multiples of 32
Network:
1 – 192.168.10.0 5 – 192.168.10.128 2 – 192.168.10.32 6 – 192.168.10.160 3 – 192.168.10.64 7 – 192.168.10.192 4 – 192.168.10.96 8 – 192.168.10.224 Step 5 – Determine your valid host and broadcast addresses. The broadcast address will always be the last address in the range or 1 bit less than the next network.
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