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| Second, we know that when two rimes have comparable sonorous duration, and one is a VV rime while the other is a VR rime, the VV rime has a greater contour tone bearing ability. Therefore, if Dur(V1) = Dur(V2)+Dur(R2), then CCONTOUR(P1) > CCONTOUR(P2); i.e., aDur(V1) > aDur(V2)+Dur(R2). Substituting Dur(V1) with Dur(V2)+Dur(R2), we get a>1, as given in (0).
(0) Range of a as determined by Heuristic 2: a>1. The choice of a should satisfy both heuristics, and it should be independent from whether Dur(V1)>Dur(V2) or Dur(V1) Let us first consider the situation Dur(V1)>Dur(V2). The range of a as determined by Heuristic 1 is a>  . Since this heuristic is relevant when Dur(V1)+Dur(R1) > Dur(V2)+Dur(R2), we know that <1. Therefore, the range of a from Heuristic 1 is not as stringent as the range a>1 from Heuristic 2. Hence, when Dur(V1)>Dur(V2), the required range for a is simply a>1.
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