134
Figure 10-2: Slope divided into n slices (after Liang and Zeng 2002). Figure 10-3: Forces acting on slice (Liang and Zeng 2002). Dividing the slipping mass into
n slices (method of slices) and applying force equilibrium results to each slice
i, results
in the following relationship ππ
ππ
= sin πΌπΌ
ππ
β
1
πΉπΉππ
[πΆπΆβ²
πΌπΌ
ππ
ππ
+ (cos πΌπΌ
ππ
β π’π’
ππ
ππ
ππ
) tan β
ππ
] + Equation 10-1)
135 Where i = 1, 2, β¦,
n Wi= Weight of slice
i.
Ξ±i= Inclination with respect to the horizontal of the base of each slice.
FS= Factor of safety.
CiβIi= Cohesion intercept at the slip surface.
li= Length of the base of the slice.
ui = Pore pressure at the base of the slice.
Ο = Friction angle of the soil at the slip surface.
Ki
= Coefficient.
R= Reduction factor.
PiIi= Interslice force.
Ki is obtained as follows
πΎπΎ
ππ
= cos πΌπΌ
ππ
) β sin tan Equation 10-2)
The
reduction factor
R is a factor that considers the soil arching effect. When the shaft spacing (
s) is comparable to the shaft diameter (
d), i.e., the extreme case where
s/d = 1,
R = 1,
the arch effect is largest, and the entire driving force of the slipping mass is transmitted to the shafts. Conversely, when
s is much larger than
d (i.e.,
s/d >> 1), the arch effect is negligible. At this point,
R approaches Rp, defined as the percent of residual soil pressure acting on the soil mass between shafts. In the extreme case that
s/d β
β,
R =
Rp. A general expression can be used to obtain
R: πΉπΉ =
1
π π
ππ
οΏ½
+ οΏ½1 β
1
π π
ππ
οΏ½
οΏ½ Equation 10-3) Values of
Rpwere obtained in a D finite element method (FEM) parametric study (Liang
and Zeng 2002), included in Table 10-1 (a) through 10-1 (c) for shaft diameters of 1, 2, and 3 feet, respectively. Equations 10-1, 10-2, and 10-3 are applied to each slice, resulting in a recursive formula for determining
Piwith initial value
Po. First,
an initial value of FS is assumed. For example, FS = 1/0.75 = 1.33 or FS=
1/0.65 = 1.53 for LRFD resistance factors Ο = 0.75 or 0.65 per AASHTO (2014) 11.6.2.3. The FS value is used in the iterative formula. If Equation 10-1 results in tension for
Pi(i.e.,
Pi< 0) at any computational step,
Pishould beset to zero in the next step to calculate
Pi+1
because stability should not rely on the typically small tension resistance of soils. Figure 10-4 shows that two cases of possible pressure distributions
that need to be evaluated, because of the possible relative movement between the shaft and soil above the shear surface. In Case I, the earth pressure down-slope of the shaft is equal to the residual value, i.e., the upslope interslice force (Pi, which is reduced for the presence of the shaft per Equation 10-1, multiplied by the percent of residual soil pressure (Rp) occurring between the shafts per Table a) through c Case II arises when the earth pressure down-slope of the shaft is equal to the at-rest value. Equations 10-4 and 10-5 are used to calculate the net shaft force for Cases I and II, respectively.